Use $\displaystyle {f{{\left({x}\right)}}}={5}{x}+{3}$ and $\displaystyle {g{{\left({x}\right)}}}={2}{x}+{1}$ to solve:

 (i)  $\displaystyle {\left({f}+{g}\right)}{\left({x}\right)}={32}$     

(ii) $\displaystyle {\left({f}-{g}\right)}{\left({x}\right)}={5}$       

(iii) $\displaystyle {\left({f}{g}\right)}{\left({x}\right)}={207}$         

(iv) $\displaystyle {\left(\frac{{f}}{{g}}\right)}{\left({x}\right)}=\frac{{23}}{{9}}$           

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