Given  f(x)=4x2(x2)5(5x+4)4(x+4)3\displaystyle {f{{\left({x}\right)}}}={4}{x}^{{2}}{\left({x}-{2}\right)}^{{5}}{\left({5}{x}+{4}\right)}^{{4}}{\left({x}+{4}\right)}^{{3}} 

List the zeroes (ex. 4, 6, -2):    

Degree:

End behavior:

As x,f(x)\displaystyle {x}\to-\infty,{f{{\left({x}\right)}}}\to 

As x+,f(x)\displaystyle {x}\to+\infty,{f{{\left({x}\right)}}}\to