y
=
5
6
x
−
7
3
\displaystyle {y}=\frac{{5}}{{6}}{x}-\frac{{7}}{{3}}
y
=
6
5
x
−
3
7
x
+
2
y
=
6
\displaystyle {x}+{2}{y}={6}
x
+
2
y
=
6
Is
(
4
,
1
)
\displaystyle {\left({4},{1}\right)}
(
4
,
1
)
a solution to the system above?
True
False
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