Solve the IVP:
d
y
d
x
=
−
6
x
+
5
y
−
5
x
+
2
y
\displaystyle \frac{{\left.{d}{y}\right.}}{{\left.{d}{x}\right.}}=\frac{{-{6}{x}+{5}{y}}}{{-{5}{x}+{2}{y}}}
d
x
d
y
=
−
5
x
+
2
y
−
6
x
+
5
y
where
y
(
2
)
=
1
\displaystyle {y}{\left({2}\right)}={1}
y
(
2
)
=
1
Solve your solution equation explicitly for
y
\displaystyle {y}
y
and enter the function in the box below:
y
=
\displaystyle {y}=
y
=
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