Given that the equation below has a solution of the form
y
=
e
r
t
\displaystyle {y}={e}^{{{r}{t}}}
y
=
e
r
t
, find
r
\displaystyle {r}
r
y
′
′
−
2
y
′
+
y
\displaystyle {y}{''}-{2}{y}'+{y}
y
′′
−
2
y
′
+
y
= 0
r
\displaystyle {r}
r
=
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\displaystyle
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Enter DNE for Does Not Exist, oo for Infinity