Find the particular solution to
y
′
′
−
3
y
′
+
2
y
=
2
e
2
t
\displaystyle {y}{''}-{3}{y}'+{2}{y}={2}{e}^{{{2}{t}}}
y
′′
−
3
y
′
+
2
y
=
2
e
2
t
y
p
\displaystyle {y}_{{p}}
y
p
=
Preview
Question 6
Submit
Try a similar question
License
[more..]
\displaystyle
Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question