Use imaginary part of the solution to the complexified version of the following ODE to find its particular solution:
y
′
′
+
5
y
′
+
6
y
=
−
208
sin
(
2
t
)
\displaystyle {y}{''}+{5}{y}'+{6}{y}=-{208}{\sin{{\left({2}{t}\right)}}}
y
′′
+
5
y
′
+
6
y
=
−
208
sin
(
2
t
)
y
p
\displaystyle {y}_{{p}}
y
p
=
Preview
Question 6
Submit
Try a similar question
License
[more..]
\displaystyle
Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question