Solve the system with the addition method:
{
4
x
−
8
y
=
6
−
2
x
+
4
y
=
3
\displaystyle {\left\lbrace\begin{array}{ccc} {4}{x}-{8}{y}&=&{6}\\-{2}{x}+{4}{y}&=&{3}\end{array}\right.}
{
4
x
−
8
y
−
2
x
+
4
y
=
=
6
3
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