Evaluate $\displaystyle {f{{\left({x}\right)}}}={\sqrt[{{4}}]{{{20}{x}^{{3}}+{12}{x}^{{2}}}}}$ for each tenth between $\displaystyle {x}=-{0.6}$ and $\displaystyle {x}={.4},$  i.e. $\displaystyle {x}=-{0.6},-{0.5},-{0.4},\ldots,{.2},{.3},{.4}.$ Round all function values to the nearest tenth.

Plot the corresponding points on the graph below.