Simplify the following expression. Assume
x
>
0
\displaystyle {x}>{0}
x
>
0
and write your answer without radicals.
(
169
x
)
1
/
2
⋅
(
2
x
2
/
5
)
\displaystyle {\left({169}{x}\right)}^{{{1}/{2}}}\cdot{\left({2}{x}^{{{2}/{5}}}\right)}
(
169
x
)
1
/
2
⋅
(
2
x
2
/
5
)
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