Solve
tan
2
(
θ
)
=
1
\displaystyle {{\tan}^{{2}}{\left(\theta\right)}}={1}
tan
2
(
θ
)
=
1
on the interval
[
0
,
π
)
\displaystyle {\left[{0},\pi\right)}
[
0
,
π
)
.
θ
=
\displaystyle \theta=
θ
=
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Question 6
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