Solve the following system of equations with the substitution method:

{x+2y=−4−3x−5y=−1\displaystyle {\left\lbrace\begin{array}{ccc} {x}+{2}{y}&=&-{4}\\-{3}{x}-{5}{y}&=&-{1}\end{array}\right.}

Answer: (x,y)=\displaystyle {\left({x},{y}\right)}=  
Enter your answers as integers or as reduced fractions in the form A/B.

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