Solve the system of equations. If the system has an infinite number of solutions, express them in terms of the parameter z. {−15x+4y+4z=−3−60x+28y−8z=1530x−8y+4z=−3\displaystyle {\left\lbrace\begin{array}{ccccccc} -{15}{x}&+&{4}{y}&+&{4}{z}&=&-{3}\\-{60}{x}&+&{28}{y}&-&{8}{z}&=&{15}\\{30}{x}&-&{8}{y}&+&{4}{z}&=&-{3}\end{array}\right.}⎩⎨⎧−15x−60x30x++−4y28y8y+−+4z8z4z===−315−3 x=\displaystyle {x}=x= Preview Question 6 Part 1 of 3 y=\displaystyle {y}=y= Preview Question 6 Part 2 of 3 z=\displaystyle {z}=z= Preview Question 6 Part 3 of 3
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