Let
f
(
x
)
=
x
x
+
4
.
\displaystyle {f{{\left({x}\right)}}}=\frac{{x}}{{{x}+{4}}}.
f
(
x
)
=
x
+
4
x
.
Find the values of
x
\displaystyle {x}
x
where
f
′
(
x
)
=
3
\displaystyle {f}'{\left({x}\right)}={3}
f
′
(
x
)
=
3
.
Give exact answers (not decimal approximations).
x
=
\displaystyle {x}=
x
=
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