If f(x)=(2x26)(3x+3)\displaystyle {f{{\left({x}\right)}}}={\left({2}{x}^{{2}}-{6}\right)}{\left({3}{x}+{3}\right)}, find:

f(x)\displaystyle {f}'{\left({x}\right)} =  

f(5)\displaystyle {f}'{\left({5}\right)} =