Given that
y
=
(
x
3
−
4
)
(
x
+
3
)
\displaystyle {y}={\left({x}^{{3}}-{4}\right)}{\left({x}+{3}\right)}
y
=
(
x
3
−
4
)
(
x
+
3
)
y
′
=
\displaystyle {y}'=
y
′
=
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