Kirchhoff's first law states that the sum of all currents that enter an electrical circuit junction is 0\displaystyle {0}. The currents enter the junction have positive sign and the currents that leave the junction have a negative sign.

I1+I2++In=0\displaystyle {I}{1}+{I}{2}+\ldots+{I}{n}={0}

If I1\displaystyle {I}{1} and I2\displaystyle {I}{2} enter a junction with 79\displaystyle \frac{{7}}{{9}} amps and 19\displaystyle \frac{{1}}{{9}} amps respectively, and I3\displaystyle {I}{3} leave the junction with 12\displaystyle -\frac{{1}}{{2}} amps, find the only other current in the junction I4\displaystyle {I}{4}.

I4\displaystyle {I}{4} amps: