Solve the given equation over the real numbers.

4(x+3[x+2(3x+4)])=4+12(6x5)\displaystyle -{4}{\left({x}+{3}{\left[{x}+{2}{\left(-{3}{x}+{4}\right)}\right]}\right)}=-{4}+{12}{\left({6}{x}-{5}\right)}

x=\displaystyle {x}=