Consider the parabola given by the equation f(x)=x2+4x3\displaystyle {f{{\left({x}\right)}}}=-{x}^{{2}}+{4}{x}-{3}

Find the following for this parabola:

A) The value of f(5)\displaystyle {f{{\left(-{5}\right)}}} is

B) The vertex is  

C) The y\displaystyle {y}-intercept is the point

D) Find the two values of x\displaystyle {x} that make f(x)=0\displaystyle {f{{\left({x}\right)}}}={0}. Write the values as a list, separated by commas:

x=\displaystyle {x}=