Given sinθ=23\displaystyle {\sin{\theta}}=\frac{{2}}{{3}}sinθ=32 where θ\displaystyle \thetaθ terminates in I, find sin(2θ)\displaystyle {\sin{{\left({2}\theta\right)}}}sin(2θ) exactly. Express your final answer as a reduced fraction without radicals in the denominator.
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