Let
f
(
x
)
=
ln
(
7
x
2
−
5
x
−
1
)
\displaystyle {f{{\left({x}\right)}}}={\ln{{\left({7}{x}^{{2}}-{5}{x}-{1}\right)}}}
f
(
x
)
=
ln
(
7
x
2
−
5
x
−
1
)
f
′
(
x
)
\displaystyle {f}'{\left({x}\right)}
f
′
(
x
)
=
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