Let
f
(
x
)
=
(
−
5
x
2
−
10
x
−
1
)
sin
(
−
2
x
)
\displaystyle {f{{\left({x}\right)}}}={\left(-{5}{x}^{{2}}-{10}{x}-{1}\right)}{\sin{{\left(-{2}{x}\right)}}}
f
(
x
)
=
(
−
5
x
2
−
10
x
−
1
)
sin
(
−
2
x
)
.
Then
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
Preview
Question 6
Question Help:
Video
Written Example
Submit
Try a similar question
License
[more..]
\displaystyle
Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question