Let
f
(
x
)
=
(
−
2
x
2
+
3
x
−
8
)
ln
(
5
x
+
4
)
\displaystyle {f{{\left({x}\right)}}}={\left(-{2}{x}^{{2}}+{3}{x}-{8}\right)}{\ln{{\left({5}{x}+{4}\right)}}}
f
(
x
)
=
(
−
2
x
2
+
3
x
−
8
)
ln
(
5
x
+
4
)
.
Then
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
Preview
Question 6
Question Help:
Video
Written Example
Submit
Try a similar question
License
[more..]
\displaystyle
Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question