Let
f
(
x
)
=
1
4
x
+
3
\displaystyle {f{{\left({x}\right)}}}=\frac{{1}}{{{4}{x}+{3}}}
f
(
x
)
=
4
x
+
3
1
. Expand and simplify:
f
(
x
+
h
)
−
f
(
x
)
h
=
\displaystyle \frac{{{f{{\left({x}+{h}\right)}}}-{f{{\left({x}\right)}}}}}{{h}}=
h
f
(
x
+
h
)
−
f
(
x
)
=
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