Using the Pythagorean Theorem.
Solve a2+b2=c2\displaystyle {a}^{{2}}+{b}^{{2}}={c}^{{2}}a2+b2=c2 for each given variable.
1) a=\displaystyle {1}{)}\ {a}=1) a= Preview Question 6 Part 1 of 3
2) c=\displaystyle {2}{)}\ {c}=2) c= Preview Question 6 Part 2 of 3
3) b=\displaystyle {3}{)}\ {b}=3) b= Preview Question 6 Part 3 of 3
Submit Try a similar question