Let
f
(
x
)
=
x
9
(
x
−
2
)
9
(
x
2
+
3
)
2
\displaystyle {f{{\left({x}\right)}}}={\frac{{{x}^{{{9}}}{\left({x}-{2}\right)}^{{{9}}}}}{{{\left({x}^{{2}}+{3}\right)}^{{{2}}}}}}
f
(
x
)
=
(
x
2
+
3
)
2
x
9
(
x
−
2
)
9
Use logarithmic differentiation to determine the derivative.
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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