Find all solutions on the interval $\displaystyle {\left[{0}^{\circ},{360}^{\circ}\right)}$. Round to the nearest hundredth. 

 $\displaystyle {18}{{\sin}^{{2}}{x}}+{15}{\sin{{x}}}-{18}={0}$ 

Separate multiple solutions with a comma. If there are no solutions please enter, "no solution" exactly.