Find all solutions on the interval [0,360)\displaystyle {\left[{0}^{\circ},{360}^{\circ}\right)}. Round to the nearest hundredth. 

 4sin2x+20sinx4=0\displaystyle {4}{{\sin}^{{2}}{x}}+{20}{\sin{{x}}}-{4}={0} 

Separate multiple solutions with a comma. If there are no solutions please enter, "no solution" exactly.