Simplify the expression. If a variable has an exponent, it should be positive. Do not use any parentheses in your answer.
(
y
5
d
2
)
−
1
\displaystyle {\left(\frac{{y}^{{5}}}{{d}^{{2}}}\right)}^{{-{{1}}}}
(
d
2
y
5
)
−
1
=
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\displaystyle