For the SSA case to yield two triangles $\displaystyle {b}{\sin{{A}}}<{a}<{b}$ must be true. Show that this is the case by calculating $\displaystyle {b}{\sin{{A}}}$, rounded to one decimal place, and filling in the blank given measurements, $\displaystyle {b}={63.8}$, $\displaystyle {a}={38.8}$ , and $\displaystyle \angle{A}={31.2}^{\circ}$ :

 $\displaystyle <{38.8}<{63.8}$ 

Now use the given measurements to solve for both possible triangles: 

Acute Triangle: $\displaystyle \angle{B}_{{1}}=$ , $\displaystyle \angle{C}_{{1}}=$ , $\displaystyle {c}_{{1}}=$ 

Obtuse Triangle: $\displaystyle \angle{B}_{{2}}=$ , $\displaystyle \angle{C}_{{2}}=$ , $\displaystyle {c}_{{2}}=$ 

Please round all solutions to the nearest tenth of a unit, if necessary.