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If x(t)=4t2+4t+6\displaystyle {x}{\left({t}\right)}=-{4}{t}^{{2}}+{4}{t}+{6}, find the position of the object at t=0.93s.\displaystyle {t}={0.93}{s}.
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Find the velocity of the object at t=0.93s.\displaystyle {t}={0.93}{s}.
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Find the acceleration of the object at t=0.93s.\displaystyle {t}={0.93}{s}.
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