Expand:
(
3
y
+
1
)
(
6
y
2
−
10
y
+
3
)
=
\displaystyle {\left({3}{y}+{1}\right)}{\left({6}{y}^{{2}}-{10}{y}+{3}\right)}=
(
3
y
+
1
)
(
6
y
2
−
10
y
+
3
)
=
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Question 6
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\displaystyle
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