Evaluate the following definite intergral. If necessary, round your final answer to three decimal places.

∫−56(−8+6t2) dt\displaystyle {\int_{{-{{5}}}}^{{6}}}{\left(-{8}+{6}{t}^{{2}}\right)}\ {\left.{d}{t}\right.}

∫−56(−8+6t2) dt=\displaystyle {\int_{{-{{5}}}}^{{6}}}{\left(-{8}+{6}{t}^{{2}}\right)}\ {\left.{d}{t}\right.}=  

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