Evaluate the following indefinite integral.
∫
1
8
+
3
t
d
t
=
\displaystyle \int\frac{{1}}{{{8}+{3}{t}}}\ {\left.{d}{t}\right.}=
∫
8
+
3
t
1
d
t
=
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Question 6
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Don't forget your
C
\displaystyle {C}
C
! And be sure to use an uppercase
C
\displaystyle {C}
C
!
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