Use implicit differentiation to find
d
y
d
x
\displaystyle \frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}
d
x
d
y
, for
y
2
=
3
y
−
8
x
\displaystyle {y}^{{2}}={3}{y}-{8}{x}
y
2
=
3
y
−
8
x
d
y
d
x
=
\displaystyle \frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}=
d
x
d
y
=
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