Use implicit differentiation to find dydx\displaystyle \frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}, for

y7=2y65x\displaystyle {y}^{{7}}=\frac{{2}}{{{y}^{{6}}}}-{5}{x}

dydx=\displaystyle \frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}=