Write the equation of the line tangent to the graph of
y
2
=
9
y
−
6
x
+
42
\displaystyle {y}^{{2}}={9}{y}-{6}{x}+{42}
y
2
=
9
y
−
6
x
+
42
at
(
1
,
−
3
)
\displaystyle {\left({1},-{3}\right)}
(
1
,
−
3
)
.
The equation is
y
=
\displaystyle {y}=
y
=
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