Let
y
=
(
4
x
2
−
10
x
−
9
)
e
−
3
x
\displaystyle {y}={\left({4}{x}^{{2}}-{10}{x}-{9}\right)}{e}^{{-{3}{x}}}
y
=
(
4
x
2
−
10
x
−
9
)
e
−
3
x
.
Then
d
y
d
x
=
\displaystyle \frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}=
d
x
d
y
=
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