Suppose
is a continuous function where
f(7)=6 and
f′(7)=5.
The equation of the line tangent to the graph of
y=f(x) at
x=7 will be
y=
So
f(x)≈
for
x close to
x=7.
Based on this,
f(7.9)≈
A solution to
f(x)=0 is
x≈
[more..]
Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question
Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity