Let $\displaystyle {f{{\left({x}\right)}}}=\sqrt{{{x}}}$.

Find $\displaystyle {x}$ close to $\displaystyle {80.92}$ where you know the exact values of both $\displaystyle {f{{\left({x}\right)}}}$ and $\displaystyle {f}'{\left({x}\right)}$. Then enter those exact values.

$\displaystyle {f{{(}}}$$\displaystyle {)}=$



$\displaystyle {f}'{(}$$\displaystyle {)}=$

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