Integrate x2x+6x3+3xdx\displaystyle \int\frac{{{x}^{{2}}-{x}+{6}}}{{{x}^{{3}}+{3}{x}}}{\left.{d}{x}\right.}.

The partial fraction decomposition is (write all terms as fractions):

\displaystyle \int dx  

The final answer is:

x2x+6x3+3xdx=\displaystyle \int\frac{{{x}^{{2}}-{x}+{6}}}{{{x}^{{3}}+{3}{x}}}{\left.{d}{x}\right.}=