Suppose
f
′
′
(
x
)
=
54
x
+
18
\displaystyle {f}{''}{\left({x}\right)}={54}{x}+{18}
f
′′
(
x
)
=
54
x
+
18
,
f
′
(
1
)
=
35
\displaystyle {f}'{\left({1}\right)}={35}
f
′
(
1
)
=
35
, and
f
(
1
)
=
4
\displaystyle {f{{\left({1}\right)}}}={4}
f
(
1
)
=
4
.
Then
f
(
x
)
=
\displaystyle {f{{\left({x}\right)}}}=
f
(
x
)
=
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