Evaluate.
∫
0
3
e
6
x
(
e
6
x
+
12
)
2
d
x
\displaystyle {\int_{{{0}}}^{{{3}}}}\frac{{{e}^{{{6}{x}}}}}{{{\left({e}^{{{6}{x}}}+{12}\right)}^{{{2}}}}}\ {\left.{d}{x}\right.}
∫
0
3
(
e
6
x
+
12
)
2
e
6
x
d
x
=
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