Let
u
⃗
=
⟨
−
1
,
−
3
,
1
,
−
2
⟩
\displaystyle \vec{{{u}}}={\left\langle-{1},-{3},{1},-{2}\right\rangle}
u
=
⟨
−
1
,
−
3
,
1
,
−
2
⟩
.
Then
∣
u
⃗
∣
=
\displaystyle {\left|{\vec{{{u}}}}\right|}=
∣
u
∣
=
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