Simplify, if possible:
z
3
+
z
2
−
76
z
+
140
z
2
−
15
z
+
56
=
\displaystyle \frac{{{z}^{{3}}+{z}^{{2}}-{76}{z}+{140}}}{{{z}^{{2}}-{15}{z}+{56}}}=
z
2
−
15
z
+
56
z
3
+
z
2
−
76
z
+
140
=
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