Use undetermined coefficients to find the particular solution to
y
′
′
+
4
y
′
−
5
y
=
3
sin
(
3
x
)
\displaystyle {y}{''}+{4}{y}'-{5}{y}={3}{\sin{{\left({3}{x}\right)}}}
y
′′
+
4
y
′
−
5
y
=
3
sin
(
3
x
)
Y
p
(
x
)
\displaystyle {Y}_{{p}}{\left({x}\right)}
Y
p
(
x
)
=
Preview
Question 6 Part 1 of 2
Now, write the general solution, using C and D for constants.
Y
(
x
)
\displaystyle {Y}{\left({x}\right)}
Y
(
x
)
=
Preview
Question 6 Part 2 of 2
Question Help:
Video
Submit
Try a similar question
License
[more..]
\displaystyle
Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question
Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question