Find the volume of the solid that lies under the paraboloid z=52x2y2\displaystyle {z}={5}^{{2}}-{x}^{{2}}-{y}^{{2}} and above region   R={(r,θ)0r5,\displaystyle {R}={\left\lbrace{\left({r},\theta\right)}{\mid}{0}\le{r}\le{5},\right.}0\displaystyle {0}πθ\displaystyle \pi\le\theta\le1\displaystyle {1}π}.\displaystyle \pi{\rbrace}.   A plot of an example of a similar solid is shown below.  (Answer accurate to 3 significant figures).




Hint: The integral and region is defined in polar coordinates.