Quadratic regression. In quadratic regression, we find the parabola which best fits the data. The easiest method for finding such a parabola is to use the principle of least squares. In mathematical terms, the parabola
y = a x 2 + b x + c \displaystyle {y}={a}{x}^{{2}}+{b}{x}+{c} y = a x 2 + b x + c is fitted to the data
( x 1 , y 1 ) , ( x 2 , y 2 ) , … , ( x n , y n ) \displaystyle {\left({x}_{{1}},{y}_{{1}}\right)},{\left({x}_{{2}},{y}_{{2}}\right)},\ldots,{\left({x}_{{n}},{y}_{{n}}\right)} ( x 1 , y 1 ) , ( x 2 , y 2 ) , … , ( x n , y n ) by minimizing the sum
S = ∑ i = 1 n [ y i − ( a x i 2 + b x i + c ) ] 2 \displaystyle {S}={\sum_{{{i}={1}}}^{{n}}}{\left[{y}_{{i}}-{\left({a}{{x}_{{i}}^{{2}}}+{b}{x}_{{i}}+{c}\right)}\right]}^{{2}} S = i = 1 ∑ n [ y i − ( a x i 2 + b x i + c ) ] 2
Determine the system of linear equations which must be satisfied by the least squares parabola.
[ \displaystyle {\left[\begin{array}{c} \\\\\\\\\\\end{array}\right.} ⎣ ⎡
∑ i = 1 n \displaystyle {\sum_{{{i}={1}}}^{{n}}} i = 1 ∑ n
∑ i = 1 n \displaystyle {\sum_{{{i}={1}}}^{{n}}} i = 1 ∑ n
∑ i = 1 n \displaystyle {\sum_{{{i}={1}}}^{{n}}} i = 1 ∑ n
] \displaystyle {\left.\begin{array}{c} \\\\\\\\\\\end{array}\right]} ⎦ ⎤
∑ i = 1 n \displaystyle {\sum_{{{i}={1}}}^{{n}}} i = 1 ∑ n
∑ i = 1 n \displaystyle {\sum_{{{i}={1}}}^{{n}}} i = 1 ∑ n
∑ i = 1 n \displaystyle {\sum_{{{i}={1}}}^{{n}}} i = 1 ∑ n
∑ i = 1 n \displaystyle {\sum_{{{i}={1}}}^{{n}}} i = 1 ∑ n
∑ i = 1 n \displaystyle {\sum_{{{i}={1}}}^{{n}}} i = 1 ∑ n
\displaystyle \ \ \ \ \ \ \ \
[ \displaystyle {\left[\begin{array}{c} \\\\\\\\\\\end{array}\right.} ⎣ ⎡
a \displaystyle {a} a
] \displaystyle {\left.\begin{array}{c} \\\\\\\\\\\end{array}\right]} ⎦ ⎤
b \displaystyle {b} b
c \displaystyle {c} c
=
[ \displaystyle {\left[\begin{array}{c} \\\\\\\\\\\end{array}\right.} ⎣ ⎡
∑ i = 1 n \displaystyle {\sum_{{{i}={1}}}^{{n}}} i = 1 ∑ n
] \displaystyle {\left.\begin{array}{c} \\\\\\\\\\\end{array}\right]} ⎦ ⎤
∑ i = 1 n \displaystyle {\sum_{{{i}={1}}}^{{n}}} i = 1 ∑ n
∑ i = 1 n \displaystyle {\sum_{{{i}={1}}}^{{n}}} i = 1 ∑ n
Consider the nitrogen/corn yield data set shown below which contains the pound of nitrogen per acre and the number of bushels of corn per acre for eight plots. Source: P.R. Johnson (1953). "Alternative functions for Analyzing a Fertilizer-Yield Relationship", Journal of Farm Economics, Vol. 35, #4, pp 519-529.
Nitrogen
Yield
0
24.9
20
43
40
50.5
60
63.2
80
73.6
120
83.1
160
95.6
180
90.1
Enter the numerical coefficients of the linear system which must be satisfied by the least squares parabola for the corn yield data set.
[ \displaystyle {\left[\begin{array}{c} \\\\\\\\\\\end{array}\right.} ⎣ ⎡
a \displaystyle {a} a
] \displaystyle {\left.\begin{array}{c} \\\\\\\\\\\end{array}\right]} ⎦ ⎤
b \displaystyle {b} b
c \displaystyle {c} c
=
Provide the equation of the least squares parabola. Enter the coefficients rounded to 4 decimal places.
y = \displaystyle {y}= y = Preview Question 6 Part 25 of 26
Use the least square parabola to predict the corn yield for a plot fertilized at a rate of 100 pounds per acre. Round your answer to 1 decimal place.
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Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 Enter DNE for Does Not Exist, oo for Infinity
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Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 Enter DNE for Does Not Exist, oo for Infinity