Solve the system by the substitution method. If there is exactly one solution, write as an ordered pair. If not, choose one of the other options.
{
6
x
+
3
y
=
12
4
x
+
y
=
6
\displaystyle {\left\lbrace\begin{array}{ccccc} {6}{x}&+&{3}{y}&=&{12}\\{4}{x}&+&{y}&=&{6}\end{array}\right.}
{
6
x
4
x
+
+
3
y
y
=
=
12
6
One solution:
No solution
Infinite number of solutions
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