Solve. Give your answer as a fraction of lowest terms. No decimals, please.
1−4(400+5x)=15(6x−20)−10\displaystyle \frac{{1}}{{-{{4}}}}{\left({400}+{5}{x}\right)}=\frac{{1}}{{5}}{\left({6}{x}-{20}\right)}-{10}−41(400+5x)=51(6x−20)−10
Submit Try a similar question